Optimal. Leaf size=77 \[ \frac{\sqrt [4]{\cos ^2(a+b x)} \sqrt{d \sec (a+b x)} (c \sin (a+b x))^{m+1} \, _2F_1\left (\frac{1}{4},\frac{m+1}{2};\frac{m+3}{2};\sin ^2(a+b x)\right )}{b c d (m+1)} \]
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Rubi [A] time = 0.0966463, antiderivative size = 77, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.087, Rules used = {2586, 2577} \[ \frac{\sqrt [4]{\cos ^2(a+b x)} \sqrt{d \sec (a+b x)} (c \sin (a+b x))^{m+1} \, _2F_1\left (\frac{1}{4},\frac{m+1}{2};\frac{m+3}{2};\sin ^2(a+b x)\right )}{b c d (m+1)} \]
Antiderivative was successfully verified.
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Rule 2586
Rule 2577
Rubi steps
\begin{align*} \int \frac{(c \sin (a+b x))^m}{\sqrt{d \sec (a+b x)}} \, dx &=\frac{\left (\sqrt{d \cos (a+b x)} \sqrt{d \sec (a+b x)}\right ) \int \sqrt{d \cos (a+b x)} (c \sin (a+b x))^m \, dx}{d^2}\\ &=\frac{\sqrt [4]{\cos ^2(a+b x)} \, _2F_1\left (\frac{1}{4},\frac{1+m}{2};\frac{3+m}{2};\sin ^2(a+b x)\right ) \sqrt{d \sec (a+b x)} (c \sin (a+b x))^{1+m}}{b c d (1+m)}\\ \end{align*}
Mathematica [C] time = 1.7626, size = 289, normalized size = 3.75 \[ \frac{8 c (m+3) \sin ^2\left (\frac{1}{2} (a+b x)\right ) \cos ^4\left (\frac{1}{2} (a+b x)\right ) F_1\left (\frac{m+1}{2};-\frac{1}{2},m+\frac{3}{2};\frac{m+3}{2};\tan ^2\left (\frac{1}{2} (a+b x)\right ),-\tan ^2\left (\frac{1}{2} (a+b x)\right )\right ) (c \sin (a+b x))^{m-1}}{b (m+1) \sqrt{d \sec (a+b x)} \left ((\cos (a+b x)-1) \left ((2 m+3) F_1\left (\frac{m+3}{2};-\frac{1}{2},m+\frac{5}{2};\frac{m+5}{2};\tan ^2\left (\frac{1}{2} (a+b x)\right ),-\tan ^2\left (\frac{1}{2} (a+b x)\right )\right )+F_1\left (\frac{m+3}{2};\frac{1}{2},m+\frac{3}{2};\frac{m+5}{2};\tan ^2\left (\frac{1}{2} (a+b x)\right ),-\tan ^2\left (\frac{1}{2} (a+b x)\right )\right )\right )+(m+3) (\cos (a+b x)+1) F_1\left (\frac{m+1}{2};-\frac{1}{2},m+\frac{3}{2};\frac{m+3}{2};\tan ^2\left (\frac{1}{2} (a+b x)\right ),-\tan ^2\left (\frac{1}{2} (a+b x)\right )\right )\right )} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.098, size = 0, normalized size = 0. \begin{align*} \int{ \left ( c\sin \left ( bx+a \right ) \right ) ^{m}{\frac{1}{\sqrt{d\sec \left ( bx+a \right ) }}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (c \sin \left (b x + a\right )\right )^{m}}{\sqrt{d \sec \left (b x + a\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{d \sec \left (b x + a\right )} \left (c \sin \left (b x + a\right )\right )^{m}}{d \sec \left (b x + a\right )}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (c \sin{\left (a + b x \right )}\right )^{m}}{\sqrt{d \sec{\left (a + b x \right )}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (c \sin \left (b x + a\right )\right )^{m}}{\sqrt{d \sec \left (b x + a\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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